# New Activation

The statement:

return N + Triangle( N-1 );

must get a value for `Triangle(N-1)`

before the addition can be done.
So the __first__ activation of `Triangle()`

causes a
__second__ activation of `Triangle()`

, this time with
a parameter of 3.
Here is how this is pictured:

### QUESTION 12:

Look at the code again. Think about the latest activation.
What does the activation `Triangle(3)`

do?

int Triangle( int N )
{
if ( N == 1 )
return 1;
else
return N + Triangle( N-1 );
}